Math

I have a triangle with one side 2y^2-3, a side with 2y^2+y+5, and the other side y^2+y+5. I had to write expression and simplify. This is what I got:
(2y^2-3)+(y^2+y+5)+(2y^2+y+5)
=5y^2+2y+7

I now have to determine the perimeter if y=3cm. I don't know how to do thus part please help!
Thank you

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asked by Cherie
  1. wherever there's a y, just plug in 3:

    5(3^2)+2(3)+7
    5(9)+2(3)+7
    45+6+7
    58

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    posted by Steve

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