I have the inequality 3y+6>0 then I got y>-2+0 since it was in standard form. To graph this would I need to shave below or above the line
>: Shade above
<: Shade below
Lines are dotted, not solid.
3 y + 6 > 0 Subtract 6 to both sides
3 y + 6 - 6 > 0 - 6
3 y > - 6 Divide both sides by 3
3 y / 3 > - 6 / 3
y > - 2
For graph go on :
w o l f r a m a l p h a . c o m
When page be open in rectangle type :
plot 3 y + 6 > 0 , y = - 5 to 5
and click option =
You will see graph
To graph the inequality 3y + 6 > 0, you first need to solve it for y.
First, subtract 6 from both sides of the inequality to isolate the y term:
3y > -6
Next, divide both sides of the inequality by 3:
y > -2
This tells us that y must be greater than -2 for the inequality to be true.
To graph this inequality on a number line, you would shade above the line at y = -2, because we want all the values of y that are greater than -2.
So, the graph would include all values of y that are to the right of -2 on the number line, with the point at -2 not included.