Can someone help me with these two problems? >.<
1. 3-x=4-3x
And
2. x/4-8=16-3/4x
What's with the >.<
are these supposed to be in-equations?
Tell me before I do them
Oh sorry just ignore those!
2nd one:
x/4- 8 = 16 - (3/4)x
multiply each term by 4 , the LCD
x - 32 = 64 - 3x
4x = 96
x = 96/4 = 24
1st one is even easier, give it a try.
Of course, I can help you with that! Let's solve each problem step by step.
Problem 1: 3-x=4-3x
To solve this equation, we want to isolate the variable x on one side of the equation.
1. Start by simplifying both sides of the equation. Distribute the negative sign on the left side and rearrange the terms.
3 - x = 4 - 3x
3 + 3x = 4 - x
2. Combine like terms on each side of the equation.
3x - x = 4 - 3
2x = 1
3. Divide both sides of the equation by 2 to solve for x.
x = 1/2
So, the solution to this equation is x = 1/2.
Now, let's move on to problem 2.
Problem 2: x/4 - 8 = 16 - 3/(4x)
Similarly, we want to isolate x on one side of the equation.
1. Start by getting rid of the fractional coefficients. To do this, we can multiply both sides of the equation by the common denominator, which is 4.
4 * (x/4) - 4 * 8 = 4 * 16 - 4 * (3/(4x))
x - 32 = 64 - (3/x)
2. Simplify both sides of the equation further.
x - 32 = 64 - (3/x)
x - 32 = 64 - 3/x
3. Multiply both sides of the equation by x to eliminate the denominator.
x * (x - 32) = (64 - 3/x) * x
x^2 - 32x = 64x - 3
4. Rearrange the terms and combine like terms.
x^2 - 96x + 3 = 0
At this point, we have a quadratic equation. To solve for x, we can either factor or use the quadratic formula.