I got this problem wrong and my teacher isnt helping me at all. we dont have books otherwise id look in it. in simplest terms can someone explain what the rights answer is? i got v= 227.35 m/s
4. A 124g baseball is dropped from a tree 11.6m above the ground. With what speed would it hit the ground if air resistance could be ignored?
g= 9.8m/s
m= 124 g- 0.124 kg
x1= 11.6m
x2= 0
v1= 0
v2= ?
V2= V1^2 +2G(X2-X1)
V2= 227.35 m/s
vf2=vi2+2ad
so take the square root of your v2
To solve this problem, we can use the equation for calculating the final velocity of an object in free-fall:
v2 = v1 + gt
Where:
v2 is the final velocity (what we're trying to find)
v1 is the initial velocity (which is 0 in this case, as the baseball is dropped)
g is the acceleration due to gravity (which is given as 9.8 m/s^2)
t is the time it takes for the baseball to fall (which we don't need to find in this case)
Given:
Mass (m) of the baseball = 124 g = 0.124 kg
Initial height (x1) = 11.6 m
Final height (x2) = 0 m
Firstly, convert the mass of the baseball to kilograms by dividing it by 1000:
m = 0.124 kg
Now, let's plug these values into the equation:
v2 = v1 + gt
v2 = 0 + (9.8 m/s^2)(11.6 m)
v2 = 113.68 m/s
So, the correct answer is v2 = 113.68 m/s, not 227.35 m/s. Therefore, it seems that you made an error in your calculation.