maths
posted by joek
Given that Sinharch(x)=ln(x+√x^2+1),determine Sinharch(2+j) in the form a+bj

Steve
√((2+j)^2+1)=2√(1+j) = 1.197+0.910j
so you want
log(3.197+1.910j)
Now recall that if z=a+bj then log(z) = logz+arccos(a/z)j
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