physics

posted by mothusi

Two blocks of 10kg and 4 kg ,respectively, are in contact with each other on frictionless,horizontal plane.They are moving at 20 metre per second.A 28N force is now applied horizontally to the opposite direction.Draw separate force diagrams for the two blocks, showing all the horizontal forces acting on a blocks,
calculate the acceleration of the blocks(-2metre per seconds squad,calculate the magnitude of the resultant horizontal force acting on the 10kg block (20N),calculate the force that the 4kg block exerts on the 10kg block and give an axplanation for the answer,for how mamy second must 28N retarding force be applied to achieve a 10metre per seconds speed in opposite direction(15seconds )

  1. bobpursley

    acceleration=force/mass=28/(10+4)=2m/s^2

    force10kg=ma=10*2
    force4kg=ma=(10*2)=20
    the4 kg is pushing against the 10kg block

    vf=vi+at
    -10=20*28/14 * t
    t=30/2=15sec

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