The current carriers in a piece of semiconducting material have a charge of 1.6 x 10^-19C. Calculate the number of charge carriers entering the material per second when the current is 3 microamps so 3 x 10^-6 amps. ?

Please help and do it step by step all parts of questions and use:
T = time(s)
I=current (amps)
Q=net charge on object (Coulombs)
N=no electrons (and write if added or removed from object and how)
E=elementary charge

This has been going on for days. The current is the charge on a carrier times the number flowing by per second. Please "cylinder" post your attempts to solve these problems with your question. Your questions are all really the same.

To calculate the number of charge carriers entering the material per second, we need to use the formula:

I = Q / T

Where:
I is the current (in amps)
Q is the net charge on the object (in coulombs)
T is the time (in seconds)

In this case, the current (I) is given as 3 x 10^(-6) amps.

Step 1: Identify the net charge on the object (Q)
Since we know the current, we can rearrange the formula to find Q:

Q = I * T

The time is not specified, so we cannot find the exact number of charge carriers entering per second. However, we can proceed by assuming a time period of 1 second, which will give us the number of charge carriers entering per second.

Step 2: Calculate the net charge on the object (Q)
With I = 3 x 10^(-6) amps and T = 1 second, we have:

Q = (3 x 10^(-6)) * (1)
Q = 3 x 10^(-6) coulombs

So, the net charge on the object is 3 x 10^(-6) coulombs.

Step 3: Calculate the number of charge carriers (N)
Now, to find the number of charge carriers (N), we'll use the fact that the charge of each carrier is given as 1.6 x 10^(-19) C (elementary charge, E). We'll divide the net charge (Q) by the charge of each carrier (E):

N = Q / E

Substituting the values we have:

N = (3 x 10^(-6)) / (1.6 x 10^(-19))
N = (3 / 1.6) * (10^(-6) / 10^(-19))
N = 1.875 * (10^13)

So, the number of charge carriers entering the material per second, assuming a time period of 1 second, is approximately 1.875 x 10^13 electrons.

Same formula as on previous, this time, solve for N.