# Precalculus 11

posted by Kayla

Determine if the given value is a solution for each quadratic. Answer yes or no.

2x^2-3x(root 2)+2=0

I know the answer is yes but I don't know how to get to that answer.

Thanks a ton! :)
Kayla

1. bobpursley

roots:

x=(3*sqrt2+-sqrt(18-16))/4

so those are the values.

2. Steve

Just to simplify a bit,

(3√2±√2)/4 = √2 or √2/2

3. Kayla

So to find that I would need to go into decimals & leave exact form & then square my final answer to know that my answer was the root of 2?

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