Algebra (Please help!)
posted by Carolyn .
Hey! I've been having a lot of trouble with this, please help!
x  7 > 10
x > __
3x < 20 (underscore under the less / greater than sign)
x < __
5a  2 < 8
a < __
2t + 8 > 4(t + 1) (underscore under the less/greater than sign)
t > __

I assume you want to solve these inequalities. Just do them the way you would work with equations.
x  7 > 10
add 7 to both sides:
x > 17
3x <= 20
divide by 3:
x <= 20/3
5a  2 < 8
add 2, then divide by 5:
5a < 10
a < 2
2t + 8 >= 4(t + 1)
2t + 8 >= 4t + 4
subtract 4 and subtract 2t:
4 >= 2t
2 >= t
or, t <= 2 
If you know how to solve equations, you should have no trouble solving inequations.
Just pretend you have an equal sign and use the same steps.
The only exception is: When you multiply or divide both sides by a negative number, you must also reverse the inequality sign
I will do the last one to illustrate
2t + 8 ≥ 4(t + 1)
2t + 8 ≥ 4t + 4 , same as you would for equation
2t 4t ≥ 4  8 , same as you would for equation
2t ≥ 4, still the same steps , BUT NOW:
I have to divide by 2, so do the arithmetic for that
but, I have to reverse the inequality sign
t ≤ 2
check my answer by taking a value of x below 2, then another above 2 in the original inequation.
notice at t = 2, the left side equals the right side
you do the others the same way 
Thank you both so much! This helps a lot :)
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