Algebra (Please help!)

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Hey! I've been having a lot of trouble with this, please help!

x - 7 > 10
x > __

3x < 20 (underscore under the less / greater than sign)
x < __

5a - 2 < 8
a < __

2t + 8 > 4(t + 1) (underscore under the less/greater than sign)
t > __

  • Algebra (Please help!) -

    I assume you want to solve these inequalities. Just do them the way you would work with equations.

    x - 7 > 10
    add 7 to both sides:
    x > 17

    3x <= 20
    divide by 3:
    x <= 20/3

    5a - 2 < 8
    add 2, then divide by 5:
    5a < 10
    a < 2

    2t + 8 >= 4(t + 1)
    2t + 8 >= 4t + 4
    subtract 4 and subtract 2t:
    4 >= 2t
    2 >= t
    or, t <= 2

  • Algebra (Please help!) -

    If you know how to solve equations, you should have no trouble solving inequations.
    Just pretend you have an equal sign and use the same steps.
    The only exception is: When you multiply or divide both sides by a negative number, you must also reverse the inequality sign

    I will do the last one to illustrate

    2t + 8 ≥ 4(t + 1)
    2t + 8 ≥ 4t + 4 , same as you would for equation
    2t -4t ≥ 4 - 8 , same as you would for equation
    -2t ≥ -4, still the same steps , BUT NOW:
    I have to divide by -2, so do the arithmetic for that
    but, I have to reverse the inequality sign

    t ≤ 2

    check my answer by taking a value of x below 2, then another above 2 in the original inequation.
    notice at t = 2, the left side equals the right side

    you do the others the same way

  • Algebra (Please help!) -

    Thank you both so much! This helps a lot :)

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