Algebra (Please help!)
posted by Carolyn
Hey! I've been having a lot of trouble with this, please help!
x  7 > 10
x > __
3x < 20 (underscore under the less / greater than sign)
x < __
5a  2 < 8
a < __
2t + 8 > 4(t + 1) (underscore under the less/greater than sign)
t > __

Steve
I assume you want to solve these inequalities. Just do them the way you would work with equations.
x  7 > 10
add 7 to both sides:
x > 17
3x <= 20
divide by 3:
x <= 20/3
5a  2 < 8
add 2, then divide by 5:
5a < 10
a < 2
2t + 8 >= 4(t + 1)
2t + 8 >= 4t + 4
subtract 4 and subtract 2t:
4 >= 2t
2 >= t
or, t <= 2 
Reiny
If you know how to solve equations, you should have no trouble solving inequations.
Just pretend you have an equal sign and use the same steps.
The only exception is: When you multiply or divide both sides by a negative number, you must also reverse the inequality sign
I will do the last one to illustrate
2t + 8 ≥ 4(t + 1)
2t + 8 ≥ 4t + 4 , same as you would for equation
2t 4t ≥ 4  8 , same as you would for equation
2t ≥ 4, still the same steps , BUT NOW:
I have to divide by 2, so do the arithmetic for that
but, I have to reverse the inequality sign
t ≤ 2
check my answer by taking a value of x below 2, then another above 2 in the original inequation.
notice at t = 2, the left side equals the right side
you do the others the same way 
Carolyn
Thank you both so much! This helps a lot :)
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