How much of h2so4 would be required to make 2.5dm3 of a 1/10 normal solution?
1)12.3g
2)24.5g
3)49.0g
d)122.5g
sulfuric acid has Heq+ =2
Normality=Heq+*Moles/volumesolution
=2*mass/molemass*2.5
mass=.1*98*2.5/2 = about 50 grams
1)12.3g
2)24.5g
3)49.0g
d)122.5g
Normality=Heq+*Moles/volumesolution
=2*mass/molemass*2.5
mass=.1*98*2.5/2 = about 50 grams