Subtract (4y^2-1) from (6y^2+2y^2+2y+4)...
gather like terms:
2y^2-4y^2 +4-(-1)
-2y^2+5
add the other terms not involved
6y^2-2y^2+2y+5
I do not understand. I got the wrong answer. Like 4y^2+5y+5
(6y^2+2y^2+2y+4)-(4y^2-1)
= (8y^2+2y+4)-(4y^2-1)
= 8y^2+2y+4-4y^2+1
= 4y^2+2y+5
No idea where the 5y came from, unless there's a typo.
To subtract (4y^2 - 1) from (6y^2 + 2y^2 + 2y + 4), you need to combine like terms. Here's how:
Step 1: Write down the equation you are trying to solve:
(6y^2 + 2y^2 + 2y + 4) - (4y^2 - 1)
Step 2: Remove the parentheses by distributing the negative sign inside:
6y^2 + 2y^2 + 2y + 4 - 4y^2 + 1
Step 3: Combine like terms by adding or subtracting coefficients of the same variables:
(6y^2 + 2y^2 - 4y^2) + (2y + 4 + 1)
Step 4: Simplify each term individually:
6y^2 + 2y^2 - 4y^2 = 4y^2
2y + 4 + 1 = 2y + 5
Step 5: Combine the simplified terms:
4y^2 + 2y + 5
Therefore, subtracting (4y^2 - 1) from (6y^2 + 2y^2 + 2y + 4) results in 4y^2 + 2y + 5.