A car is traveling at 5.0 m/s to the right when, at t=0, the driver applies her foot to the gas to cause an acceleration of 3 m/s2.
How fast is the driver traveling at t = 5 seconds?
How far has the driver traveled in those 5 seconds?
a car is traveling to the right? Normally, they travel straight ahead or backwards.
vf=vi+a*t
d= vi*t+1/2 at^2
62.5?
To find out how fast the driver is traveling at t = 5 seconds, we need to use the kinematic equation:
v = u + at
Where:
v = final velocity (what we're trying to find)
u = initial velocity = 5.0 m/s
a = acceleration = 3.0 m/s^2
t = time = 5 seconds
Substituting the values into the equation, we have:
v = 5.0 m/s + (3.0 m/s^2)(5.0 s)
v = 5.0 m/s + 15.0 m/s
v = 20.0 m/s
Therefore, the driver is traveling at 20.0 m/s at t = 5 seconds.
To find out how far the driver has traveled in those 5 seconds, we can use another kinematic equation:
s = ut + (1/2)at^2
Where:
s = distance traveled (what we're trying to find)
u = initial velocity = 5.0 m/s
a = acceleration = 3.0 m/s^2
t = time = 5 seconds
Substituting the values into the equation, we have:
s = (5.0 m/s)(5.0 s) + (0.5)(3.0 m/s^2)(5.0 s)^2
s = 25.0 m + (0.5)(3.0 m/s^2)(25.0 s^2)
s = 25.0 m + (0.5)(3.0 m/s^2)(625.0 s)
s = 25.0 m + (0.5)(1875.0 m/s)
s = 25.0 m + 937.5 m
s = 962.5 m
Therefore, the driver has traveled 962.5 meters in those 5 seconds.