Math
posted by Dave .
Evaluate the integral of x * sqrt(x1) from [1,2].
I let u=x1 and du=1*dx, but then I can't get rid of the x to start integrating?
The answer in the book is 16/15.

Let
u^2 = x1
2u du = dx
x = u^2+1
∫x√(x1) dx
= ∫(u^2+1)(u)(2u du)
...
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