Why is 5% NaOH insoluble in HCl?
I am not sure what you mean. You get water and Na+ ions and Cl- ions, in other words salt water. It gives off some heat though so might be exciting.
The two solutions are not insoluble.
To understand why 5% NaOH (sodium hydroxide) is insoluble in HCl (hydrochloric acid), we need to consider the chemical properties of these substances.
NaOH is a strong base, while HCl is a strong acid. When a strong acid reacts with a strong base, they undergo a neutralization reaction where the acid donates a hydrogen ion (H+) to the base, forming water and a salt.
In the case of NaOH and HCl, the neutralization reaction can be represented as follows:
HCl + NaOH -> NaCl + H2O
In this reaction, NaCl (sodium chloride) and H2O (water) are formed. Sodium chloride is a highly soluble salt in water, meaning it dissolves completely. Water is also a polar solvent, capable of dissolving many ionic compounds.
However, in a solution of 5% NaOH, the NaOH is already dissolved in water. When we add HCl to this solution, there is already an excess of NaOH present as dissolved molecules. The HCl will react with the NaOH that is in solution, forming more NaCl and water. Since sodium chloride is highly soluble, it will remain dissolved in the solution.
In summary, 5% NaOH is insoluble in HCl because the NaOH is already dissolved in water, and the additional HCl will react with the NaOH, forming a soluble salt (NaCl) and water.