Questions LLC
Login
or
Sign Up
Ask a New Question
Questions
Math
m^2-n^2=4(mn)^1/2 if m=tanx+secx then n=?
1 answer
That √(mn) is a problem. Try setting
n = secx-tanx and see where that takes you.
You can
ask a new question
or
answer this question
.
Related Questions
If e^y=tanx, 0<x<pi/2 what is dy/dx in terms of x?
A.secxcscx B.sec^2x C.secx D.sin x sec x
simplify: tanx/secx+1
Evaluate the integral of
(secx)^2 * (tanx)^3 *dx I started out with letting u=secx and du=secx*tanx*dx , but then I am kind of
tan(3x) + 1 = sec(3x)
Thanks, pretend 3x equals x so tanx + 1 = secx we know the law that 1 + tanx = secx so tanx + 1 becomes
How do you verify:
1.) sinxcosx+sinx^3secx=tanx 2.) (secx+tanx)/(secx-tan)=(secx+tanx)^2 I tried starting from the left on both
I can't find the integral for
(tanx)^(6)*(secx)^(2) I tried splitting up tanx into (tanx)^2*(tanx)^4 and let the latter equal
1/tanx-secx+ 1/tanx+secx=-2tanx
so this is what I did: =tanx+secx+tanx-secx =(sinx/cosx)+ (1/cosx)+(sinx/cosx)-(1/cosx)
Verify the identity.
(secx + tanx)/(secx - tanx) = (1 + 2sinx + sin(^2)x)/cos(^2)x
Trigonometric Identities
Prove: (tanx + secx -1)/(tanx - secx + 1)= tanx + secx My work so far: (sinx/cosx + 1/cosx +
npr=3024 find r
(2)dy/dx=secx-tanx/secx+tanx. plz help