The width of a rectang;e is w=r-5 and the area is r^3-24-5. What is the length? Please tell me how you solved. Thank you.
You probably didn't typed your question correct.
Try again.
By the way:
A = w * l
l = A / w
Then long division give the length.
This really did not help at all. The question is, The width of a rectangle is (r – 5) and the area is (r^3 – 24r – 5). What is the length of the rectangle? If you could help people with this that would be great instead please do not pop your nose in. Dont give the answers just show us how to do it with examples please.
To find the length of the rectangle, we will use the formula for the area of a rectangle: Area = Length × Width.
Given:
Width (w) = r - 5
Area = r^3 - 24 - 5
Substitute the given values into the formula for area:
r^3 - 24 - 5 = (r - 5) × Length
Now, let's simplify:
r^3 - 29 = r × Length - 5 × Length
We can rearrange the equation to solve for the length:
r × Length = r^3 - 29 + 5 × Length
r × Length - 5 × Length = r^3 - 29
Factor out the Length on the left side:
Length × (r - 5) = r^3 - 29
Replace the width expression (w = r - 5) with Length × (r - 5):
Length × w = r^3 - 29
Now, we can solve for the Length:
Length = (r^3 - 29) / w
So, to find the length, you substitute the expressions for the width and area into the formula, which gives you (r^3 - 29) divided by (r - 5).