A swimming pool :40m and 15 mlong and wide .shallow endsare1.5m and 3m deep.if borlttom of pool slopes uniformluly,fimd the amount in lotelres required to fill the pool
you really need to proofread your posts ...
The cross-section is a trapezoid with area
A = (3/2 + 3)/2 * 15 m^2
So, the volume of the pool is A*40 m^3
now just convert that figure to "lotelres"
To find the amount of water in liters required to fill the swimming pool, you need to calculate the volume of the pool. The pool consists of two sections: the shallow end and the deep end.
First, let's calculate the volume of the shallow end:
Length of the shallow end = 15 meters
Width of the shallow end = 15 meters
Depth of the shallow end = 1.5 meters
Volume of the shallow end = Length × Width × Depth
= 15 m × 15 m × 1.5 m
= 337.5 cubic meters
Next, let's calculate the volume of the deep end:
Length of the deep end = 15 meters
Width of the deep end = 15 meters
Depth of the deep end = (3 meters - 1.5 meters) = 1.5 meters (since the bottom slopes uniformly)
Volume of the deep end = Length × Width × Depth
= 15 m × 15 m × 1.5 m
= 337.5 cubic meters
Now, let's calculate the total volume of the pool by adding the volumes of the shallow and deep ends:
Total volume of the pool = Volume of shallow end + Volume of deep end
= 337.5 cubic meters + 337.5 cubic meters
= 675 cubic meters
Finally, convert the volume from cubic meters to liters:
1 cubic meter = 1000 liters
Amount of water required to fill the pool = Total volume of the pool × 1000
= 675 cubic meters × 1000
= 675,000 liters
Therefore, approximately 675,000 liters of water are required to fill the swimming pool.