3X+Y-11 and -2X+Y=1 X= Y=

y = 1+2x

3x+(1+2x) = 11
...

Given

3x+y=11 call as eq 1
-2x+y=1 call as eq 2
Subtract 1&2 and consider simaltaneously

We get "y" will be cancelled

So, 5x=10
x=10/5
X=2

Substitute x=2 in eq 1
3x+y=11
3(2)+y=11
6+y=11

Y=11-6

Y=5

Therefore x=2 and y=5

To find the values of X and Y, you can use the method of solving a system of equations by substitution or elimination. Let's use the substitution method.

Given the equations:
1) 3X + Y - 11 = 0
2) -2X + Y = 1

Step 1: Solve equation 2) for Y in terms of X:
-2X + Y = 1
Y = 2X + 1

Step 2: Substitute the value of Y, from Step 1, into equation 1):
3X + (2X + 1) - 11 = 0
5X - 10 = 0

Step 3: Solve for X:
5X = 10
X = 10 / 5
X = 2

Step 4: Substitute the value of X into equation 2) to find Y:
-2(2) + Y = 1
-4 + Y = 1
Y = 1 + 4
Y = 5

Therefore, the solution is:
X = 2
Y = 5