An empty beaker weighs 39.17 g.
a) When completely filled with water, the beaker and its contents have a total mass of 406.25 g. What volume does the beaker hold? Use d =1.00 g/mL as the density of water.
for A i got 367.08 but I don't know for this
b) How much would the beaker and its contents weigh if it was completely filled with mercury? The density of mercury is d =13.5 g/mL..
volume=367.08milliliters
mass with Hg multipy 367.08*13.5 grams
a) To find the volume of water held by the beaker, we can use the formula:
Volume = Mass / Density
Given that the mass of the beaker and its contents (water) is 406.25 g and the density of water (d) is 1.00 g/mL, we can substitute these values into the formula:
Volume = 406.25 g / 1.00 g/mL
Volume = 406.25 mL
Therefore, the beaker holds a volume of 406.25 mL.
b) To find out how much the beaker and its contents would weigh if it was completely filled with mercury, we need to calculate the mass first. The mass can be calculated using the formula:
Mass = Volume x Density
Given that the volume of the beaker is the same as in part a (406.25 mL) and the density of mercury (d) is 13.5 g/mL, we can substitute these values into the formula:
Mass = 406.25 mL x 13.5 g/mL
Mass = 5488.125 g
Therefore, the beaker and its contents would weigh 5488.125 grams if filled with mercury.
To find the volume of the beaker in part (a), you can subtract the initial weight of the empty beaker from the total weight when it is filled with water. Since the density of water is given as 1.00 g/mL, you can equate the weight of the water to its volume.
a) Volume of water in the beaker:
First, calculate the weight of water in the beaker:
Weight of water = Total weight of beaker + water - Weight of empty beaker
Weight of water = 406.25 g - 39.17 g = 367.08 g
Since density = mass/volume, you can rearrange the formula to solve for volume:
Volume = Mass/Density
Substitute the values in:
Volume = 367.08 g / 1.00 g/mL
Volume ≈ 367.08 mL
Therefore, the beaker holds approximately 367.08 mL of water.
b) To find how much the beaker and its contents would weigh if it was filled with mercury, you can use the same approach as in part (a). The density of mercury is given as 13.5 g/mL.
Weight of mercury in the beaker:
Weight of mercury = Volume of beaker × Density of mercury
Substitute the values in:
Weight of mercury = Volume of beaker × 13.5 g/mL
Since the volume of the beaker was not given explicitly, you can convert its weight to volume using the density of water.
Volume of beaker = Weight of beaker / Density of water
Volume of beaker = 39.17 g / 1.00 g/mL
Volume of beaker = 39.17 mL
Now, substitute this value in:
Weight of mercury = 39.17 mL × 13.5 g/mL
Weight of mercury ≈ 527.895 g
Therefore, if the beaker was completely filled with mercury, it would weigh approximately 527.895 g.