calculate the moles of oxygen atom in 6.2 g of calcium carbonate?
To calculate the moles of oxygen atoms in calcium carbonate, we need to follow a series of steps. First, we need to determine the number of moles of calcium carbonate using its molar mass. Then, we'll use the balanced chemical equation to find the ratio of oxygen atoms per formula unit of calcium carbonate. Finally, we can calculate the moles of oxygen atoms by multiplying the moles of calcium carbonate by the ratio of oxygen atoms.
Step 1: Calculate moles of calcium carbonate
The molar mass of calcium carbonate (CaCO3) can be calculated by adding the atomic masses of calcium (Ca), carbon (C), and three oxygen (O) atoms.
Molar mass of CaCO3 = (40.08 g/mol Ca) + (12.01 g/mol C) + (3 * 16.00 g/mol O)
Molar mass of CaCO3 = 40.08 g/mol + 12.01 g/mol + 48.00 g/mol
Molar mass of CaCO3 = 100.09 g/mol
Now, we can calculate the moles of calcium carbonate by dividing its mass by its molar mass.
moles of CaCO3 = mass of CaCO3 / molar mass of CaCO3
moles of CaCO3 = 6.2 g / 100.09 g/mol
Step 2: Determine the ratio of oxygen atoms in calcium carbonate
The balanced chemical equation for the decomposition of calcium carbonate is:
CaCO3(s) -> CaO(s) + CO2(g)
From this equation, we can see that for every one formula unit of calcium carbonate that decomposes, one mole of oxygen atoms is obtained.
Step 3: Calculate moles of oxygen atoms
Now, we can calculate the moles of oxygen atoms by multiplying the moles of calcium carbonate by the ratio of oxygen atoms.
moles of oxygen atoms = moles of CaCO3 * 1
Substituting the values, we have:
moles of oxygen atoms = (6.2 g / 100.09 g/mol) * 1
After performing the calculation, you will obtain the moles of oxygen atoms in 6.2 g of calcium carbonate.