Can someone walk me through this?
For the equation Ax + By = C (where A, B, C are real numbers) what is the slope (in terms of the traditional y = mx+ b) and state any restrictions.
Please!
the slope is -A/B
So, of course, B cannot be zero.
That gives the equation Ax=C which is a vertical line, so the slope is undefined.
Could you explain that to me? ^^^
@Ms.Sue! Can you help me?
To find the slope of the equation Ax + By = C in terms of the traditional y = mx + b format, we need to rearrange the given equation.
1. Start by isolating the y term.
Ax + By = C
By = -Ax + C
2. Divide both sides of the equation by B to solve for y.
y = (-A/B)x + (C/B)
Now, we can see that the equation is in the form y = mx + b, where the coefficient of x, (-A/B), represents the slope (m) and the constant term (C/B) represents the y-intercept (b).
Therefore, the slope of the equation Ax + By = C in terms of y = mx + b is -A/B. This means that the slope of the line represented by this equation is -A/B.
As for the restrictions, there are no specific restrictions mentioned in the question. However, it is worth noting that the equation Ax + By = C represents a straight line, and the slope (-A/B) should be a nonzero real number for the line to exist. If A and B are both zero, the equation becomes an identity, and if B is zero, the equation becomes a vertical line parallel to the y-axis.