A defective clock is set correctly at 12 nn.However it registers only fifteen mins. for each hr.In how many hr.will it again register the correct time?
32 hours (8:00 p.m.of the next day)
Can you please enlighten more how it is. Thank you.
If the time in the defective clock says 12:15 p.m., then,it means 1:00 p.m. in the normal clock.
So, an hour in the def.clock is equal to 4 hours in norm.clock. I list the time in the defective clock and the original time.
Defect. time/No. of Hours/Orig.time
12pm-1pm / 4hrs / 12pm-4pm
1pm-2pm / +4hrs / 4pm-8pm
2pm-3pm / +4hrs / 8pm-12am
3pm-4pm / +4hrs / 12am-4am
4pm-5pm / +4hrs / 4am-8am
5pm-6pm / +4hrs / 8am-12pm
6pm-7pm / +4hrs / 12pm-4pm
7pm-8pm / +4hrs / 4pm-8pm
TOTAL TIME: 32hrs (observe that the def.time and orig.time meet at 8pm)
To answer this question, we need to understand that the defective clock is registering time 15 minutes behind the actual time for every hour that passes.
Since the clock is set correctly at 12:00 noon (12:00 PM), it will register 11:45 AM when it's actually 12:00 PM. This means that it's behind by 15 minutes.
To calculate how many hours it will take for the clock to again register the correct time, we need to divide the time difference between the actual time and the clock time by the amount of time the clock loses for each hour.
Let's do the calculation:
Time difference: 15 minutes = 15/60 hours = 1/4 hours.
Loss per hour: 15 minutes = 15/60 hours = 1/4 hours.
Now, we can divide the time difference by the loss per hour:
Time difference (1/4 hours) divided by Loss per hour (1/4 hours) = 1/4 hours รท 1/4 hours = 1.
Therefore, it will take 1 hour for the clock to register the correct time again.