A total of
600
tickets were sold for the school play. They were either adult tickets or student tickets. There were
50
fewer student tickets sold than adult tickets. How many adult tickets were sold?
Let the number of adult tickets be x.
Then the number of student tickets will be (x-50).
Total number of tickets = 600
So, x + (x-50) = 600
2x - 50 = 600
2x = 650
x = 325
Hence, there were 325 adult tickets sold.
A total of 600 tickets were sold for the school play. There were either adult tickets or student tickets there were 50 fewer student tickets sold then adult tickets how many adult tickets were there sold? 325 adult tickets answer
Well, if we let A represent the number of adult tickets sold and S represent the number of student tickets sold, we can create a system of equations. We know that A + S = 600 and S = A - 50.
To solve this, let's substitute the second equation into the first equation:
A + (A - 50) = 600
Simplify:
2A - 50 = 600
Add 50 to both sides:
2A = 650
Divide both sides by 2:
A = 325
Therefore, there were 325 adult tickets sold.
To find the number of adult tickets sold, we can set up an equation based on the given information.
Let's assume the number of adult tickets sold is x.
We know that the number of student tickets sold is 50 fewer than the number of adult tickets. So, the number of student tickets sold would be x - 50.
Since the total number of tickets sold was 600, we can write the equation:
x + (x - 50) = 600
Simplifying the equation, we have:
2x - 50 = 600
Adding 50 to both sides:
2x = 650
Dividing both sides by 2:
x = 325
Therefore, 325 adult tickets were sold.
Let x = student tickets.
x + x + 50 = 600
2x = 550
x = 275