A minor league baseball team plays 95 games in the season if the team won 15 more than three times as many games as they lost how many wins and losses did they the team have I need the losses
To determine the number of losses, we need to find out how many wins the team had first. Let's break down the information provided:
- The team plays 95 games in the season.
- The team won 15 more than three times as many games as they lost.
Let's use variable substitution to solve the equation step by step.
Let's assume the number of losses is represented by 'L.'
According to the given information, the number of wins can be expressed as (3L + 15).
The total number of games played is the sum of wins and losses, which is 95:
Wins + Losses = 95
(3L + 15) + L = 95
Combining like terms:
4L + 15 = 95
Subtracting 15 from both sides:
4L = 80
Dividing both sides by 4:
L = 20
Therefore, the team had 20 losses in the season.
If they lost x games, then we have
x + 3x+15 = 95
Losses - 20
Wins -75