When 4.2g of NaHCO3 is added to a solution of CH3COOH Weighing 10g, it is observed that 2.2g of co2 is realised into the atmosphere . The residue left is found to be 12g . Show that this observations are in agreement with the law of conservation of mass?
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To show that these observations are in agreement with the Law of Conservation of Mass, we need to calculate the total mass of the reactants and the total mass of the products and compare them.
First, let's identify the balanced chemical equation for the reaction between NaHCO3 and CH3COOH:
NaHCO3 + CH3COOH -> CO2 + H2O + NaCH3COO
From the given information, we have:
Mass of NaHCO3 = 4.2g
Mass of CH3COOH = 10g
Mass of CO2 released = 2.2g
Residue left = 12g
Now, let's calculate the total mass of the reactants:
Total mass of reactants = Mass of NaHCO3 + Mass of CH3COOH
Total mass of reactants = 4.2g + 10g
Total mass of reactants = 14.2g
Next, let's calculate the total mass of the products:
Total mass of products = Mass of CO2 released + Residue left
Total mass of products = 2.2g + 12g
Total mass of products = 14.2g
Since the total mass of the reactants (14.2g) is equal to the total mass of the products (14.2g), we can conclude that these observations are in agreement with the Law of Conservation of Mass. According to this law, the mass of the reactants must be equal to the mass of the products in a chemical reaction.