if out of two
numbers, one number is
increased by 10% and other
number by 20%,find percentage
increase in the product of the
two numbers
product=(1.1n)(1.2m)=nm*1.31
looks like 31 percent
To find the percentage increase in the product of two numbers, you need to follow these steps:
1. Assume the two numbers are x and y.
2. Calculate the product of the two numbers: p = x * y.
3. Increase one number by 10%: x_new = x + (0.10 * x) = 1.10 * x.
4. Increase the other number by 20%: y_new = y + (0.20 * y) = 1.20 * y.
5. Calculate the new product: p_new = x_new * y_new = (1.10 * x) * (1.20 * y).
6. Calculate the percentage increase in the product:
percentage_increase = ((p_new - p) / p) * 100.
Let's calculate the percentage increase in the product:
Given:
- One number is increased by 10%, so the new value of x is 1.10 * x.
- The other number is increased by 20%, so the new value of y is 1.20 * y.
Let's assume the initial numbers are x = 100 and y = 200:
- The initial product, p = 100 * 200 = 20,000.
- The new product, p_new = (1.10 * 100) * (1.20 * 200) = 132 * 240 = 31,680.
Now, we can calculate the percentage increase in the product:
percentage_increase = ((p_new - p) / p) * 100
= ((31,680 - 20,000) / 20,000) * 100
= (11,680 / 20,000) * 100
= 0.584 * 100
= 58.4%.
Therefore, the percentage increase in the product of the two numbers is 58.4%.