Solve then sketch the graph of y=x^2(4-x)
(kindly answer it step by step please. Needed for my studies tonight. Final exam for tommorrow. Really need your help maam/sir.). this is on algebraic curves. Thankyou !
you know it has
a double root at x=0
so, the graph is tangent to the x-axis at (0,0)
The graph crosses the x-axis at x=4
y is positive for large negative values of x, so the graph comes down from the left, touches (0,0), goes back up and crosses at (4,0) on its way down to the right.
Use what you know in general about the shape of cubics. The graph is at
http://www.wolframalpha.com/input/?i=x^2%284-x%29,+-3%3C%3Dx%3C%3D6