How many 2-digit numbers can be formed using only the digits 2, 3, 5, and 6. if the digits are not repeated within a number?
11
12
10
2
Try figuring it out. I'll get you started.
23
32
25
52
26
62
etc.
12
To find the number of 2-digit numbers that can be formed using the digits 2, 3, 5, and 6, without repetition, you can use the concept of permutations.
A permutation of a set is an arrangement of its elements in a particular order. In this case, we need to find the number of permutations of the 4 given digits when taken 2 at a time.
To solve this, we can use the formula for permutations:
nPr = n! / (n - r)!
Where n is the total number of items in the set (in this case, 4 digits) and r is the number of items we need to select (in this case, 2 digits).
Using the formula, we can calculate the number of 2-digit numbers:
nPr = 4! / (4 - 2)!
= 4! / 2!
= (4 * 3 * 2 * 1) / (2 * 1)
= 24 / 2
= 12
So, the number of 2-digit numbers that can be formed using the digits 2, 3, 5, and 6 without repetition is 12.