i figured out the ratio its 1.10 , don't know how to get the second part please help!! my understanding is not good enough to answer part 2

Pretend you have two containers, one filled with ethyl alcohol and the other filled with benzene. How would you show the distance light travels through each container in 3 ns? How would you show the difference in the distance light traveled in each fluid?

I don't know!

1. Determine the ratio for the speed of light in ethyl alcohol (n=1.36) to the speed of light in benzene (n=1.50).

2. If light travels for 3.0ns in ethyl alcohol, how much further will it travel in this material than it would in benzene? answer will be in terms of speed of light in benzene, Vbenzene.

So, if their ratio is 1.1, you have determined that

Ve/Vb = 1.1

since distance = speed * time

3*10^-9 Ve = 1.1*3*10^-9 Vb = 3.3*10^9 Vb

So, De-Db = 0.3*10^-9 Vb

thank you steve!

To answer the second part of your question, you need to use the ratio you found (1.10) and the given time (3.0ns) to determine the difference in the distance light travels in each material.

Here's how you do it:

1. Start with the given time, 3.0ns.
2. Multiply the time by the speed of light in ethyl alcohol to get the distance light travels in ethyl alcohol. Let's call this distance Dethanol.
Dethanol = 3.0ns * speed of light in ethyl alcohol
3. Multiply the distance Dethanol by the ratio we found (1.10) to get the equivalent distance in benzene. Let's call this distance Dbenzene.
Dbenzene = Dethanol * ratio
4. Simplify the equation using the given information, speed of light in benzene (Vbenzene), and the distance in benzene (Dbenzene).
Dbenzene = Dethanol * ratio
Dbenzene = Dethanol * 1.10
Dbenzene = 3.0ns * speed of light in ethyl alcohol * 1.10
Dbenzene = 3.0ns * speed of light in benzene

So, the difference in the distance that light travels in each material is equal to the speed of light in benzene multiplied by the given time (3.0ns). The answer will be in terms of the speed of light in benzene (Vbenzene).

Remember to substitute the value of the speed of light in benzene (Vbenzene) to get the numerical answer.