Find the quantity of heat produced when 100ml of 0.1N HCL is completely neutralised with NAOH solution

Do you have any other information? You need, at least, the heat of neutralization for H^+ + OH^- ==> H2O. I don't remember but think it's about 55 kJ/mol.

HCl + NaOH ==> NaCl + H2O
You have mols HCl = M x L = 0.1 x 0.1 = 0.01 mols.
So approx 55 kJ/mol x 0.01 mol = approx 0.55 kJ. You can look up that number and go from there.