draw a triangle ABC in which AB:AC is 1:3 and BC 6 cm and angle c=75
No such triangle can exist
Proof:
let AB=x, then AC=3x
by the cosine law,
x^2 = 9x^2+36-2(6)(3x)cos75
8x^2 - 9.32x + 36 = 0
for which b^2-4ac= -165.14
Thus there are no real values possible for x