chem 12
posted by George
for the equilibrium
2HI(g) H2(g) + I2 k eq = 8.0
2.0 mol of HI are placed in a 4.0 L container, and the system is allowed to reach equilibrium. Calculate the equilibrium concentration of all three gases.
Inital
2HI 0.5mol/l
H2 =0
I2=0
change
2HI= 2x
H2=+x
I2=+x
equilibrium
2HI = 0.52x
H2= x
I2=x
keq= H2 x I2/ HI^2
8.0= (x) (x)/0.52x
taking sqr root of both sides
2.828=x/0.52x
0.2154=x
so 0.2154 mol/L of H2 and I2 at equilibrium and
2HI = 2x=2(0.2154)= 0.4308
0.50.4308=0.069
2HI=0.069 mol/L
If you could look this over to see if I have done this right. I appreciate any help you can give. Thank you for taking the time to offer your help. Again it is greatly appreciated.

bobpursley
keq= H2 x I2/ HI^2
8.0= (x) (x)/0.52x
what happened to the square in the denominator?
Respond to this Question
Similar Questions

college chemistry
When a sample of HI(g) (5.825 mol) is placed in 320.0 L reaction vessel at 702.0 K and allowed to come to equilibrium the mixture contains 1.052 mol of H2(g). What is the equilibrium concentration (mol/L) of HI(g)? 
Chemistry
Consider the following equilibrium: 2HI(g) *are in equilibrium with* H2(g) = I2(g) Keq = 81.0 A 2.00L container is initially filled with 4.00 mol HI. Calculate the [HI] at equilibrium. *I don't know how to put the equilibrium sign … 
chem
For the reaction: A+B <> 2C (all gases) 2.0 mol A, 2.8 mol B and 1.0 mol C are placed in a 2.0 L container and allowed to reach equilibrium. When equilibrium is established [C]=0.75 M. Calculate all equilibrium concentrations. … 
chem
For the reaction: N2+3H2 <> 2NH3 1.000 mol N2 and 1.000 mol H2 are placed in a 1.000 L container and allowed to establish equilibrium. When equilibrium is established the [N2] =0.921M. Calculate the equilibrium concentrations … 
chem
For the reaction: N2+3H2<>2NH3 4.000 mol N2, 2.000 mol H2, and 6.000 mol NH3 are placed in a 2.000 L container and allowed to reach equilibrium. When equilibrium is established the [H2]=2.77 M. Calculate the equilibrium concentrations … 
chem12
for the equilibrium 2HI(g) H2(g) + I2 k eq = 8.0 2.0 mol of HI are placed in a 4.0 L container, and the system is allowed to reach equilibrium. Calculate the equilibrium concentration of all three gases. Inital 2HI 0.5mol/l H2 =0 … 
chem12
1.0 mol of each of the gases, CO, H20, CO2 and H2 are placed in a 2.00L container and allowed to reach equilibrium. It is found at equilibrium 0.40 mol of CO is present. Calculate the value of K eq for the system. C0(g) + H20(g) … 
chem 12
1.0 mol of each of the gases, CO, H20, CO2 and H2 are placed in a 2.00L container and allowed to reach equilibrium. It is found at equilibrium 0.40 mol of CO is present. Calculate the value of K eq for the system. C0(g) + H20(g) … 
chem12
2HI(g)H2(g) + I2(g) k eq= 8.0 2.0 mol of HI are placed in a 4.0L container, and the system is allowed to reach equilibrium. Calculate the equilibrium concentration of all three gases Initial 2HI=0.5 mol/L H2= 0 I2=0 change 2HI= 2x … 
chem12
2HI(g)H2(g) + I2(g) k eq= 8.0 2.0 mol of HI are placed in a 4.0L container, and the system is allowed to reach equilibrium. Calculate the equilibrium concentration of all three gases Initial 2HI=0.5 mol/L H2= 0 I2=0 change 2HI= 2x …