a 5 gram rubber ball is released from a height of 7 meter above flat surface on the moon. gravitational acceleration on the moon is 1.62 meters per second squared. assume that no energy is lost from frictional drag. what is the velocity, in units of meters per second, of the rubber ball the instant before it
plssssssss as fast as u can
vf^2=vi^2+2a*distance
To find the velocity of the rubber ball just before it hits the flat surface on the moon, we can use the principles of motion and gravitational acceleration.
We can start by calculating the time it takes for the ball to fall from a height of 7 meters on the moon. We can use the equation:
s = ut + (1/2)gt^2
where:
- s is the distance or height (7 meters)
- u is the initial velocity (0 m/s since it is released from rest)
- g is the gravitational acceleration on the moon (1.62 m/s^2)
- t is time
Plugging in the values, the equation becomes:
7 = 0*t + (1/2)*1.62*t^2
Simplifying, we get:
7 = (0.81)*t^2
Dividing both sides by 0.81:
8.641975 = t^2
Taking the square root of both sides:
t ≈ 2.94 seconds
Now that we have the time it takes for the ball to fall, we can find the velocity just before it hits the surface using the equation:
v = u + gt
where:
- v is the final velocity
- u is the initial velocity (0 m/s)
- g is the gravitational acceleration on the moon (1.62 m/s^2)
- t is the time (2.94 seconds)
Plugging in the values, the equation becomes:
v = 0 + 1.62 * 2.94
Calculating:
v ≈ 4.75 m/s
Therefore, the velocity of the rubber ball just before it hits the flat surface on the moon is approximately 4.75 meters per second.
To find the velocity of the rubber ball the instant before it hits the flat surface on the moon, we can use the laws of motion and the principles of conservation of energy.
Step 1: Calculate the potential energy (PE) of the rubber ball at the initial height.
Potential energy is given by the formula PE = m * g * h, where m is the mass of the ball, g is the gravitational acceleration on the moon, and h is the height.
PE = 5 g * 1.62 m/s^2 * 7 m = 57.15 J (Joules)
Step 2: Convert potential energy to kinetic energy.
Since energy is conserved, the potential energy of the ball at the initial height will be equal to the kinetic energy (KE) just before it hits the surface.
KE = PE = 57.15 J (Joules)
Step 3: Use the formula for kinetic energy to calculate the velocity.
Kinetic energy is given by the formula KE = 0.5 * m * v^2, where v is the velocity.
0.5 * 5 g * v^2 = 57.15 J
2.5 g * v^2 = 57.15 J
v^2 = 57.15 J / (2.5 g)
v^2 = 22.86 m^2/s^2
Step 4: Take the square root of both sides to find the velocity.
v = √(22.86 m^2/s^2)
v ≈ 4.78 m/s
Therefore, the velocity of the rubber ball the instant before it hits the flat surface on the moon is approximately 4.78 meters per second.