Math
posted by jiya
3 cos (ωt + 2) + 4 sin (ωt + 1) as A cos (ωt + φ) .
A = ? φ= ?

Steve
try the addition formulas:
3 cos (ωt + 2) = 3(cosωt cos2  sinωt sin2)
4 sin(ωt+1) = 4(sinωtcos1 + cosωtsin1)
adding them up you get
3cosωtcos2+4cosωtsin1
+ 4sinωtcos1  3sinωtcos2
Now, according to wolframalpha.com, that gives
A = √(2524sin(1))
tanφ =
sec(1)(4sin(1)+3cos(2))

4  6sin(1)
so φ ≈ 3.736
See
http://www.wolframalpha.com/input/?i=3+cos+%28t+%2B+2%29+%2B+4+sin+%28t+%2B+1%29
But I don't see any clear path to getting there.
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