# Algebra

posted by GummyBears

1.Mary is selling her craft to earn money she sells her bracelets for \$6 and her necklaces for \$10 her goal is to make at least \$120 in sales which of the following represents three possible solutions to the problem

A.6x+10y<120
(5,10),(10,5),and(15,0)are three possible solutions.

B.6x+10y>=120
(5,9),(10,6),and(15,3)are three possible solutions.

C.6x-10y<120
(5,5),(10,10),and(15,15)are three possible solutions.

D.7x+5y<=140
(7,21),(14,14),and(21,7)are three possible solutions.

I think it's A.6x+10y<120
(5,10),(10,5),and(15,0)are three possible solutions. please correct me if I'm wrong.

I think it's between B and D. is it D

1. Damon

6x+10y must be AT least 120, She would prefer more
so

6x+10y >= 120
which is B

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