If sec (t) = 13/12 then,find the value of cos (t)
cos = 1/sec
1. if 13 cos =12, find the value of sec a+ sin a?
2.if 9 cos-7=0, find the value of coseca?
To find the value of cos(t) when sec(t) = 13/12, we can use the reciprocal identity between cosine and secant.
The reciprocal identity states that sec(t) is equal to 1/cos(t).
Given that sec(t) = 13/12, we can set up the equation:
1/cos(t) = 13/12
To solve for cos(t), we can cross-multiply:
12 = 13 * cos(t)
Now, divide both sides of the equation by 13:
12/13 = cos(t)
Therefore, the value of cos(t) is 12/13.