construct a parallogam ABCD such that AB=6cm,ABC=120degree and BC=5cm
I am assuming you are using a straight edge and compass.
Draw a straight line.
construct an equilateral triangle on that line, easy to do
the exterior angle will be 120°
Proceed from there
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To construct a parallelogram ABCD with the given conditions, follow the steps below:
1. Draw a line segment AB of length 6 cm.
2. At point A, construct an angle of 120 degrees using a protractor.
3. Measure a distance of 5 cm from point A along the line AB and mark point C.
4. Draw a line segment BC of length 5 cm from point B to point C.
5. Draw a line segment CD parallel to AB, starting from point C.
6. Measure a distance of 6 cm along the line CD, starting from point C, and mark point D.
7. Draw a line segment AD connecting points A and D to complete the parallelogram ABCD.
Make sure the lines AB and CD are parallel to each other and likewise for lines BC and AD. You can use a ruler and a protractor to ensure accurate measurements and angles.
Therefore, by following these steps, you will construct a parallelogram ABCD with AB = 6 cm, ∠ABC = 120 degrees, and BC = 5 cm.