algebra
posted by Alisha
Joy is planning a party. One game she decides to play is bobbing for apples. She divides her apples into three amounts, thinking that putting a different number in each samesized bucket might make ti more fun. Three friends are helping her. Joy puts 1/2 of her apples plus 1/2 apple into Becky's bucket. She then puts 1/2 of the remaining apples plus 1/2 into Gayle's bucker. She then puts 1/2 of the remaining apples plus 1/2 apple into Bonnie's bucket. One apple is left over, which Joy eats. How many apples did she start with? How many apples went into each helper's bucket?

Steve
original amount: x apples
Becky gets (x+1)/2, leaving Joy (x1)/2
Gayle gets (x+1)/4, leaving Joy (x3)/4
Bonnie gets (x+1)/8, leaving 1 left over
x  (x+1)/2  (x+1)/4  (x+1)/8 = 1
x = 15
or, working backwards, there were
((1*2+1)*2+1)*2+1 = 15 apples to start
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