5. A circuit is supplied with 30 VDC and contains three resistors connected in series. The value or R1 is 80Ω, the value of R2 is 1,000Ω , and the value of R3 is 4,200Ω . What is the voltage drop across R2?

Question

5. A circuit is supplied with 30 VDC and contains three resistors connected in series. The value or R1 is 80Ω, the value of R2 is 1,000Ω , and the value of R3 is 4,200Ω . What is the voltage drop across R2?

A. 5.68 V
B. 2.14 V
C. 4.61 V
D. 6.82 V

I keep coming up with even number 6 and that is not an option. I did everything 4 times. Calculated the total circuit current which came up as 0.006. Did I do that wrong? That's the only thing I can think of where I may have goofed.

Thanks! :)

Answer 1

I did it for the zillionth time and came up with 5.68V... Is that correct?

Answer 2

E = 30 Vdc

R1 = 80 Ohms
R2 = 1,000 Ohms
R3 = 4,200 Ohms
V2 = ?

I = E/(R1+R2+R3) = 30/5,280 = 0.00568A

V2 = I * R2 =

Answer 3

To find the voltage drop across R2, we can use the formula:

V = I * R

where V is the voltage drop, I is the current flowing through the resistor, and R is the resistance of the resistor.

First, let's calculate the total resistance for the series circuit:

R_total = R1 + R2 + R3
= 80Ω + 1,000Ω + 4,200Ω
= 5,280Ω

Next, let's calculate the total current flowing through the circuit using Ohm's Law:

V_source = I_total * R_total
30 V = I_total * 5,280Ω

Now, solve for I_total:

I_total = 30 V / 5,280Ω
≈ 0.00568 A (approx.)

You mentioned calculating it as 0.006 A, which seems close.

Finally, let's calculate the voltage drop across R2:

V_R2 = I_total * R2
= 0.00568 A * 1,000Ω
= 5.68 V

So the voltage drop across R2 is approximately 5.68 V, which matches option A.

Answer 4

To calculate the voltage drop across resistor R2 in a series circuit, you need to determine the total resistance of the circuit first. The total resistance in a series circuit is the sum of the individual resistances:

R_total = R1 + R2 + R3

In this case, R1 = 80Ω, R2 = 1,000Ω, and R3 = 4,200Ω. Therefore:

R_total = 80Ω + 1,000Ω + 4,200Ω
R_total = 5,280Ω

The next step is to calculate the current flowing through the circuit using Ohm's Law:

I = V / R_total

Where V is the supply voltage of 30 VDC and R_total is the total resistance of 5,280Ω:

I = 30 V / 5,280 Ω
I ≈ 0.00568 A

(Note: The given circuit current should be 0.00568 A, not 0.006 A.)

Now that you have the circuit current, you can calculate the voltage drop across resistor R2 using Ohm's Law:

V_R2 = I * R2

Plugging in the values, we get:

V_R2 = 0.00568 A * 1,000Ω
V_R2 = 5.68 V

Therefore, the voltage drop across resistor R2 is 5.68 V.

Looking at the answer choices, option A (5.68 V) matches the calculated voltage drop. Thus, the correct answer is A.