IF THE VOLTAGE IS DOUBLED AND THE RESISTOR IS NOT CHANGED, WHAT WILL HAPPEN TO THE CURRENT IN A RESISTIVE CIRCUIT
E/R -> (2E)/R = 2E/R
In a resistive circuit, Ohm's Law states that the current flowing through the circuit is directly proportional to the voltage and inversely proportional to the resistance. Mathematically, Ohm's Law can be represented as:
I = V / R
Where:
I = Current
V = Voltage
R = Resistance
Now, if the voltage is doubled and the resistor is not changed, we can use Ohm's Law to determine the effect on the current.
Let's assume the original voltage is V1, and the original current is I1. Since the resistor remains the same, the resistance is constant, given by R.
Using Ohm's Law, we can find the original current as:
I1 = V1 / R
Now, if the voltage is doubled, the new voltage is 2V1. The resistance remains the same (R). We can find the new current (I2) as:
I2 = (2V1) / R
I2 = 2(V1 / R)
As we can see, the current doubles when the voltage is doubled and the resistance is constant.