1. What is the value of z so that -9 and 9 are both solutions of x^2+z=103?
a) -22
b) 3
c) 22
d) 184
2. What is the value of b in the triangle below? The triangle has one side that is 3b and another that is just b. The area of the triangle is 24in.^2.
a) -4 in
b) 4 in
c) no solution
d) -4 and 4
The first question is the most important, please help me with that one first. :) If you do not know the second one then do not worry about that problem. Thank you!
1. C (+/-7)
2. D (no solution)
3. B (12x)
4. B (4 in)
5. C (22)
Whether -9 or 9, x^2 = 81
81 + z = 103
Nevermind, I understand now. Thank you. :)
Thank you @chance, you are a life saver <3 <3
So when we're asked about finding the solution of a quadratic equation, we're supposed to find the value of x?
jnkjn
To find the value of z such that both -9 and 9 are solutions of x^2 + z = 103, we can follow these steps:
Step 1: Substitute -9 for x in the equation x^2 + z = 103:
(-9)^2 + z = 103
Simplifying:
81 + z = 103
Step 2: Subtract 81 from both sides of the equation:
z = 103 - 81
Simplifying:
z = 22
Therefore, the value of z that satisfies the equation when -9 and 9 are solutions is 22.
Option c) 22 is the correct answer to the first question.
Regarding the second question about finding the value of b in a triangle, I'm sorry, but without further information, it is not possible to determine the value of b.