Me. And Mrs. Jefferson have a total of $5170 in the bank. At the end of the month, mr. Jefferson deposits $450 into his account, and news Jefferson deposits $626 into her account. They now have an equal amount of money in their accounts. How much money did each of them have at first?
Don't know please help
it's over nine thousand!!!!!!
$5170 + $450 + $626 = $6246
$6246 / 2 = $3123 ...= halves
So originally...
Mr. J: $3123 - $450 = $2673
and
Ms. J: $3123 - $626 = $2497
To find out how much money each of them had at first, we can set up an equation based on the given information.
Let's assume that Mr. Jefferson had x dollars and Mrs. Jefferson had y dollars initially.
We are given the following information:
1. At the end of the month, Mr. Jefferson deposits $450 into his account.
After the deposit, Mr. Jefferson would have x + $450.
2. Mrs. Jefferson deposits $626 into her account.
After the deposit, Mrs. Jefferson would have y + $626.
3. They now have an equal amount of money in their accounts.
According to this statement, we can set up the equation:
x + $450 = y + $626
Now, we know that their total amount in the bank is $5170.
So, we can also set up another equation:
x + y = $5170
We have a system of two equations:
x + $450 = y + $626
x + y = $5170
To solve this system, we can use the method of substitution or elimination.
Let's use the method of substitution:
From the second equation, we can express x in terms of y:
x = $5170 - y
Now, substitute this expression for x in the first equation:
($5170 - y) + $450 = y + $626
Simplifying:
$5170 - y + $450 = y + $626
Combine like terms:
$5620 - y = y + $626
Add y to both sides:
$5620 = 2y + $626
Subtract $626 from both sides:
$4994 = 2y
Divide both sides by 2:
$2497 = y
Now that we have the value of y, we can substitute it back into the second equation to find x:
x + $2497 = $5170
Subtract $2497 from both sides:
x = $5170 - $2497
x = $2673
Therefore, Mr. Jefferson initially had $2673, and Mrs. Jefferson initially had $2497.