vertex form:y-4=-(x-4)^2
what is the question?
The vertex form of the equation above is
y=(x-4)^2 + 4 for a parabola whose vertex is 4, 4
Oh. Sorry
vertex: y-4=-(x-4)^2
standard:?
intercept?
vertex form:
y = - (x-4)^2 + 4
your text or your notes should have the definitions and properties of that form
Thanks
The given equation is in the vertex form of a quadratic equation, which is:
y - k = a(x - h)^2
In this form, the vertex of the quadratic equation is represented by the coordinates (h, k).
Comparing the equation y - 4 = -(x - 4)^2 with the vertex form, we can determine the vertex as follows:
The vertex is located at the point (h, k), so in this case, the vertex is at (4, 4).
The value of "a" determines the direction of the quadratic function's graph. Since "a" is negative in the given equation, the graph opens downwards.
Now that we have identified the vertex, we can use this information to answer any questions related to the graph or properties of the quadratic equation.