# MA

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Can a/b and (a+b)/b ever form a proportion? Why or why not?

• MA -

well, let's try it ...

a/b = (a+b)/b
times b, if b ≠0

a = a+b
then b = 0
but now we have a contraction, so .....

or

cross - multiply
ab = ab + b^2
b^2 = 0
b = 0 , but that would make a/b undefined,

so what do you think?

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