MA
posted by DAWN .
Can a/b and (a+b)/b ever form a proportion? Why or why not?

well, let's try it ...
a/b = (a+b)/b
times b, if b ≠0
a = a+b
then b = 0
but now we have a contraction, so .....
or
cross  multiply
ab = ab + b^2
b^2 = 0
b = 0 , but that would make a/b undefined,
so what do you think?
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