posted by me .
A line contains the points (8, 9) and (–12, –7). Using point-slope form, write the equation of the line that is parallel to the given line and that passes through (–5, –15).
slope of the line going through the first two points
= (-7-9)/(-12-8) = -16/-20 = 4/5
so going through new point (-5,-15) with the same slope
y+15 = (4/5)(x+5)
do whatever you have to do further, but that is in
line passes through ( 1, -5 ) and ( -3, 7).
a.) Write an equation for the line point-slope form.
B, Rewrite the equation in slope-intercept form.