physics
posted by Ann .
A Honda Civic travels in a straight line along a road. Its distance x from a stop sign is given as a function of time t by the equation x(t)= α t2− β t3, where α = 1.43m/s2 and β = 4.60×10−2m/s3 .
1)Calculate the average velocity of the car for the time interval t=0 to t1 = 2.04s
2)Calculate the average velocity of the car for the time interval t=0 to t2 = 4.09s .
3)Calculate the average velocity of the car for the time interval t1 = 2.04s to t2 = 4.09s .

velocity=d distance/dtime= d/dt (a t^2Bt^3)
velocity=2A*t 3Bt^2
a) average= (v(2.04)v(o))/2.04 where
v(2.04)= 2A*2.043B*2.04^2 where A, B are given.
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