Given(3x+3)/(6y+1)=3,find the value of7x/3y.
3x+3 = 0
3x = -3
x= -1
6y+1 = 0
6y= -1
y = -1/6
7(-1)/ 3(-1/6)
the value of 7x/3y is 14
from the given equation,
18y + 3 = 3x+3
18y = 3x
x = 6y
then 7x/3y
= 42y/(3y)
= 42/3
= 14
=
why3x+3=0 ??
okay i got it!thanks!!
good question, Olivia, since if 3x+3 = 0 we would have
0/(6y+1) = 3
0 = 3 which would be nonsense.
Jonel was just "lucky" to get the correct answer, since
x = -1 works in the simplified equation x = 6y
but not in the original equation.
I did magic
To find the value of 7x/3y, first we need to solve the given equation (3x+3)/(6y+1) = 3 for x or y. Let's solve it for x.
Step 1: Cross multiply the equation to eliminate the fraction:
(3x+3)/(6y+1) = 3
Cross multiplying, we get:
(3x+3) = 3(6y+1)
Step 2: Distribute 3 to both terms in the parentheses:
3x+3 = 18y+3
Step 3: Subtract 3 from both sides to isolate 3x:
3x = 18y
Step 4: Divide both sides by 3 to solve for x:
x = 18y/3
x = 6y
Now we know that x = 6y.
Step 5: Substitute this value of x into the expression 7x/3y:
7x/3y = 7(6y)/3y
Simplifying:
7x/3y = 42y/3y
Step 6: Simplify further by canceling out the common y terms:
7x/3y = 42/3
7x/3y = 14
Therefore, the value of 7x/3y is 14.