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Solve
3 log x = 1 + log (4x+5)/ log 2

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    3 log x = 1 + log (4x+5)/ log 2

    That dividing logs stuff is quite unusual for introductory log problems. I will solve

    3 log x = 1 + log (4x+5) - log 2
    x^3 = 10*(4x+5)/2
    2x^3-40x-50 = 0
    2(x-5)(x^2+5x+5) = 0
    and that's easy

    If you really did mean to divide the logs, then I cannot find any real roots.

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