math
posted by amit .
If x=a^2/3a^2/3 then find x^3 3x=?

let a^(2/3) = y for easier typing
then x = y  1/y
= (y^2  1)/y
x^3 = (y^6 3y^4 + 3y^2  1) / y^3
= (a^4  3a^(8/3) + 3a^(4/3)  1)/a^2
or
a^2  3a^(2/3) + 3a^(2/3)  a^2
3x = 3a^(2/3)  3a^(2/3)