posted by Mona .
A current of 3.40 A is passed through a Ni(NO3)2 solution for 1.80 hours. How much nickel is plated out of the solution?
Made a mistake that Dr. Bob222 caught in an earlier post. See your earlier post for corrections.
Convert hr to seconds (s):
1.80hrs*(60 min/1 hr)*(1 min/60s)= time in s
Solve for charge:
1 mole of e^-s=9.65 x 10^4 C
Solve for moles:
C*(1 mole/9.65 x 10^4 C)=moles of e^-s
The half reaction is the following:
Ni2+ + 2e ---> Ni
So, 2 moles of e^- is needed for 1 mole of Ni:
Solve for moles of Ni:
moles of e^-s*(1 mole of Ni/2 mole of e^-)= moles of Ni
Solve for mass:
moles of Ni*( 58.69 g/mole)= mass of Ni
I am doing something wrong I keep getting the wrong answer
Instead of us guessing, why don't you show your work so we can find the error.